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x^2+99x+127=0
a = 1; b = 99; c = +127;
Δ = b2-4ac
Δ = 992-4·1·127
Δ = 9293
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-\sqrt{9293}}{2*1}=\frac{-99-\sqrt{9293}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+\sqrt{9293}}{2*1}=\frac{-99+\sqrt{9293}}{2} $
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